(2x^2+13x+18)/(x+4)=0

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Solution for (2x^2+13x+18)/(x+4)=0 equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(2*x^2+13*x+18)/(x+4) = 0

2*x^2+13*x+18 = 0

2*x^2+13*x+18 = 0

DELTA = 13^2-(2*4*18)

DELTA = 25

DELTA > 0

x = (25^(1/2)-13)/(2*2) or x = (-25^(1/2)-13)/(2*2)

x = -2 or x = -9/2

(x+9/2)*(x+2) = 0

((x+9/2)*(x+2))/(x+4) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x+9/2 )

x+9/2 = 0 // - 9/2

x = -9/2

x in { -2, -9/2 }

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